Question: Physics homework? Please help?
A hospital attendant exerts a horizontal force of 60N on a gurney with a patient on it and accelerates at 0.4 m/s^2. The patient is 65kg and the gurney is 30kg. What is the magnitude of the frictional force opposing the motion.
BY F(net) = F(applied) - F(friction)
=>ma = Fa -Ff
=>Ff = Fa - ma
=>Ff = 60 - (65+30) x 0.4
=>Ff = 22 N
I would think
The summation of forces in the x direction= Mass x Acceleration (in X direction)
Forces in Y direction=Mass x Acceleration (in Y direction)
The total mass of the patient and gurney is 95 KG
Acceleration in Y is equal to 0 m/s/s
acceleration is X is equal to 0.4 m/s/s
forces in x direction are the push (60N) and the force of friction. So the sum in the x-direction is the difference. 60N-X
Solve for X by plugging into first equation mentioned
(65 + 30) = 95kg.
F = (ma) = 38N. would be required, no friction. So:
(60 - 35) = 25N. frictional force.