Type in your question!We only want to offer the best possible answers to you.

Question: Physics homework? Please help?

A hospital attendant exerts a horizontal force of 60N on a gurney with a patient on it and accelerates at 0.4 m/s^2. The patient is 65kg and the gurney is 30kg. What is the magnitude of the frictional force opposing the motion.

Relation Questions:

• Can someone please explain to me the ideas of half life and count rate? in terms of radioactive decay. Thanks!?
• Two workers are delivering a load mass M along an uphill road with a length L and elevatin angle theta. Worker?
• What is the wavelength of a 4.80-eV photon and the de Broglie wavelength of a 4.80-eV electron?
• How to write description of a led?

Answer:

BY F(net) = F(applied) - F(friction)
=>ma = Fa -Ff
=>Ff = Fa - ma
=>Ff = 60 - (65+30) x 0.4
=>Ff = 22 N

I would think

The summation of forces in the x direction= Mass x Acceleration (in X direction)

Forces in Y direction=Mass x Acceleration (in Y direction)

The total mass of the patient and gurney is 95 KG

Acceleration in Y is equal to 0 m/s/s

acceleration is X is equal to 0.4 m/s/s

forces in x direction are the push (60N) and the force of friction. So the sum in the x-direction is the difference. 60N-X

Solve for X by plugging into first equation mentioned

60N-X=(95)(0.4)

x=22N

(65 + 30) = 95kg.
F = (ma) = 38N. would be required, no friction. So:
(60 - 35) = 25N. frictional force.