Question: 7th graded math help!!!!!!!!!!!!!!!!!!!!!!!?

Jose is paying for a \$6 meal using bills in his wallet. He has four \$1 bills, three \$5 bills, and two\$10 bills. If he selects two bills at random, one at a time from his wallet, what is the probability that he will choose a \$1 bill and a \$5 bill to pay for the meal?

Relation Questions:

Answer:

I believe it would be 12/56 because with probability, whenever you see "and" it means multiply the two fractions. So there are 9 bills total. First he picks a bill and there is a 4/9 chance he will get a \$1 bill. So that's your first fraction. Then, he will reach and take another bill and there is a 3/8 chance he will get a five. The denominator changes because there is one fewer bill since he already took one \$1 bill out. Then, you take these fractions and multiply them to get 12/72. I hope that helps! Really sorry if I'm wrong :p. This is a great site http://www.regentsprep.org/Regents/math/algtrig/ATS6/LTheo.htm for help with that stuff.

1 dollars bills would be 4/9
5 dollar bills would be 3/9

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